Final answer:
There can be eight different types of gametes formed by the genotype AaBbCc, because each of the three heterozygous gene loci can produce two types of alleles.
Step-by-step explanation:
The number of different types of gametes that can be formed by the genotype AaBbCc is 8. Each gene locus can produce two types of gametes because each parental genotype is heterozygous (Aa, Bb, Cc), that is, each has one dominant and one recessive allele.In order to determine the number of different types of gametes that can be formed by the genotype AaBbCc, we need to consider the number of different possibilities for each gene. As there are three genes in this genotype, we need to calculate the product of the number of possibilities for each gene.
For each gene, there are 2 possibilities: one allele from each parent. Therefore, for the genotype AaBbCc, there are 2 x 2 x 2 = 8 different types of gametes that can be formed.
To determine the number of gametes, we use the formula 2^n, where n is the number of gene loci with heterozygosity. In this case, n=3 (Aa, Bb, Cc). So the calculation would be 2^3, which equals 8.
The possible gametes are: ABC, ABc, AbC, Abc, aBC, aBc, abC, and abc. This is explained by Mendel's law of independent assortment, which states that allele pairs separate independently during the formation of gametes.