Question

Please help and solve; big points
3/2 ∜(2(x-6)^3 )+4=16

Answer 1

x ≈ 18.7

Explanation:

This is a big equation, so let's break it down a bit.

`(3)/(2) \sqrt[4]{(2(x-6) ^3 )} +4=16`

Let's start by isolating the radical which is x.

So subtract 4 from both sides :

`(3)/(2) \sqrt[4]{(2(x-6) ^3)}`
`=12`

Now multiply both sides by 2 to get rid of the fraction :

`3\sqrt[4]{(2(x-6)^3)} = 24`

Now divide both sides by 3 to get rid of the number out of the poly root :

`\sqrt[4]{2(x-6) ^3}`
`=8`

Now take both sides of the equation to the power of 4 :

`2x^3 - 36x^2+216x-432=4096`

And lastly, solve :

`x = 18.69920` which is rounded up to
`x` ≈
`18.7`