Final answer:
The probability that both OTF and ST will deliver on time cannot be calculated without the correct probability of ST making the delivery on time. Assuming there was a mistake and the probability of ST delivering on time is 1/3, then the compounded probability would be 1/4.
Step-by-step explanation:
The subject of this question is Mathematics, specifically focusing on the topic of probability. The grade level is most likely High School, as the question involves compounded probability which is typically covered at this level.
To calculate the probability that OTF and ST will both deliver in time, we multiply the independent probabilities of each event happening. However, there seems to be a misunderstanding in the question, as it states the probability of ST not making the delivery on time is 2/3. Unless we have the probability of ST making the delivery on time, we cannot find the probability of both delivering on time. Therefore, a clarification is needed for the probability of ST delivering on time.
If the probability of ST making the delivery on time was actually intended to be 1/3, then the probability of both OTF and ST delivering on time would be calculated as follows: (3/4) * (1/3) = 3/12 or 1/4. However, without the correct probability for ST, we cannot provide an answer to the question in its current state.