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What is the resistance in a light bulb that has a 61 Volt battery and a current of 12 Amps?

User Justderb
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1 Answer

13 votes
13 votes

Answer:

5.1 Ω

Step-by-step explanation:

Basic Law v = ir

so v/i = r = 61/12 = 5.1 Ω

User Karadous
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