Answer: Given:
4 shirts, 4 pairs of trousers , and 2 hats is $560
9 shirts, 9 pairs of trousers , and 6 hats is $1,290
1) Let x be the price of 1 shirt
Let y be the price of 1 pair of trousers
Let z be the price of 1 hat
2) 4x + 4y + 2z = 560
3) 9x + 9y + 6z = 1,290
4) (9x + 9y + 6z) / 3 = 1,290 / 3
3x + 3y + 2z = 430
5)
4x + 4y + 2z = 560
- (3x + 3y + 2z = 430)
x + y = 130
6) 3(x+y) + 2z = 430
3(130) + 2z = 430
390 + 2z = 430
2z = 430 - 390
2z = 40
z = 40/2
z = 20
7) x = price of 1 shirt; y = price of 1 pair of trousers ; z = price of 1hat
x + y = 130 ; z = 20
130 + 20 = 150
The price of 1 shirt, 1 pair of trousers, and 1 hat is $150.
So this is not impossible!
-chiyoku toga