Final answer:
To calculate the number of grams of NH₃ produced, use the stoichiometry of the balanced chemical equation. Convert the mass of nitrogen to moles, determine the moles of hydrogen using the stoichiometry, and then calculate the moles of ammonia produced. Finally, convert the moles of ammonia to grams.
Step-by-step explanation:
To calculate the number of grams of NH₃ produced by the reaction of 6.82 grams of nitrogen with hydrogen, we need to use the stoichiometry of the balanced chemical equation. According to the equation N₂ + 3 H₂ → 2 NH₃, we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
First, we need to calculate the number of moles of nitrogen using its molar mass. The molar mass of nitrogen (N₂) is 28.02 g/mol. So, 6.82 grams of nitrogen is equal to 6.82 g / 28.02 g/mol = 0.243 mol of nitrogen.
Since the stoichiometry of the reaction is 1:3 for nitrogen to hydrogen, we can calculate the number of moles of hydrogen by multiplying the number of moles of nitrogen by 3. Therefore, 0.243 mol of nitrogen react with 0.243 mol * 3 mol/mol = 0.729 mol of hydrogen.
Finally, we can use the mole ratio from the balanced equation to calculate the number of moles of ammonia produced. From the equation, we know that 1 mole of nitrogen reacts to produce 2 moles of ammonia. So, 0.243 mol of nitrogen will produce 0.243 mol * 2 mol/mol = 0.486 mol of ammonia.
To calculate the number of grams of ammonia, we can use the molar mass of ammonia (NH₃), which is 34.08 g/mol. So, 0.486 mol of ammonia is equal to 0.486 mol * 34.08 g/mol = 16.59 grams of ammonia.