Question

What is the mechanical advantage of a screw with a pitch of 0.05 inches and a head with a diameter of 0.30 inches if you turn it with a screwdriver whose diameter is 1.5 inches? I think the equation to solve this would be:

Circumference witch is equal to 3.1416 x the Diameter witch is 1.5 inch. ÷ by the pitch witch is 0.05 inch.

Answer 1

The mechanical advantage of a screw with a pitch of 0.05 inches and turned by a screwdriver with a 1.5-inch diameter is approximately 94.248.

Step-by-step explanation:

The mechanical advantage of a screw can be determined by the formula MA = (circumference of the handle) / (pitch of the screw). To find the circumference of the handle (which is the part of the screwdriver that you turn), use the diameter of the screwdriver. Since Circumference = π x diameter, for a screwdriver with a diameter of 1.5 inches, the circumference is 3.1416 x 1.5=4.7124 inches. Then, divide this circumference by the pitch of the screw, which is 0.05 inches. Therefore, the mechanical advantage (MA) is 4.7124 / 0.05 = 94.248. This means you multiply your input force by approximately 94.248 times when turning the screwdriver.