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A hiker walks 3 km north, 4 km east, and 6 km south. What is the magnitude of the resultant displacement of the hiker?​

User Pudgeball
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The magnitude of the hiker's resultant displacement after walking 3 km north, 4 km east, and 6 km south is 5 kilometers, calculated using Pythagoras' theorem on a right-angled triangle formed by the net north-south and east-west movement.

To determine the magnitude of the resultant displacement of a hiker who walks 3 km north, 4 km east, and 6 km south, we can use vector addition. The hiker's initial displacement north is partially canceled out by the displacement to the south. Viewing this as a right-angled triangle where the legs represent the total north-south and east-west displacement, we have one leg of 3 km north minus 6 km south, resulting in a net movement of 3 km south, and the other leg remains at 4 km east.

To find the magnitude of the resultant displacement, we use Pythagoras' theorem. The magnitude is the hypotenuse of the triangle, calculated as:

\(\sqrt{(3 km)^2 + (4 km)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 km\)

In conclusion, the magnitude of the hiker's resultant displacement is 5 kilometers.

User BCunningham
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