Final answer:
Given a velocity of 9.0 m/s and a time airborne of 0.80 seconds, Mary's friend can leap across a maximum distance of 7.2 meters.
Step-by-step explanation:
To determine how long of a pool Mary's friend can possibly leap across, we need to use the given values for speed and time airborne. Mary's friend averages 9.0 m/s and can stay airborne for 0.80 seconds. To calculate the distance of the jump, we multiply the velocity by the time.
The formula to apply is distance = velocity × time. By inserting the given values, we get:
distance = 9.0 m/s × 0.80 s = 7.2 meters
Therefore, the maximum distance Mary's friend can leap across a pool is 7.2 meters. This assumes a horizontal jump without any vertical displacement interfering with the horizontal distance covered.