96.7k views
0 votes
An Olympic size pool is 50.0 m long and 25.0 m wide. What is the mass in

kilograms of the water required to fill the pool to a depth of 11.77 ft.? (First find
the volume of the pool, then use the Density of water = 1.00 g/mL to find the
mass)

User Eddy Pronk
by
9.6k points

1 Answer

2 votes

Final answer:

To find the mass of the water required to fill the pool to a certain depth, we need to calculate the volume of the pool, then use the density of water to find the mass.

Step-by-step explanation:

To find the mass of the water required to fill the pool to a certain depth, we first need to find the volume of the pool. The volume of a rectangular pool can be calculated by multiplying the length, width, and depth of the pool.

In this case, the length of the pool is 50.0 m, the width is 25.0 m, and the depth is 11.77 ft. We need to convert the depth from feet to meters since the other dimensions are given in meters. 1 ft is approximately 0.3048 m, so the depth in meters is 11.77 ft * 0.3048 m/ft = 3.589296 m.

Now we can calculate the volume of the pool: Volume = length * width * depth = 50.0 m * 25.0 m * 3.589296 m = 4493.745 m^3.

Next, we can use the density of water, which is 1.00 g/mL or 1000 kg/m^3, to find the mass of the water. Mass = density * volume = 1000 kg/m^3 * 4493.745 m^3 = 4493745 kg.

User Mohammad Tabbara
by
8.1k points