Question

An airplane can go from 100 m/s to 0 m/s in 11 seconds. At the same rate of acceleration, what distance will it require to stop from a speed of 150 m/s?

Answer 1

The distance required to stop from a speed of 150 m/s is 112.5 m.

Step-by-step explanation:

To find the distance required to stop from a speed of 150 m/s, we can use the formula:

vf^2 = vi^2 + 2ad

Where vf is the final velocity (0 m/s), vi is the initial velocity (150 m/s), a is the acceleration (which is constant), and d is the distance. Rearranging the formula, we get:

d = (vf^2 - vi^2) / (2a)

Plugging in the values, we have:

d = (0^2 - 150^2) / (2(-100))

d = (-22500) / (-200)

d = 112.5 m