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The present population of a village is 30,000 . If it is increased at the rate of 10% per annum, what will be the population after 2 years?​

User Jenk
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Final answer:

The population of the village after 2 years, growing at an annual rate of 10%, will be 36,300.

Step-by-step explanation:

The present population of a village is 30,000 and it is increasing at a rate of 10% per annum. To find out the population after 2 years, we can use the formula for compound growth which is:

P(t) = P0 (1 + r)^t

where:

  • P(t) is the future population
  • P0 is the present population
  • r is the annual growth rate in decimal form
  • t is the number of years

Substituting the given values:

  1. Convert the percentage rate to decimal by dividing by 100: r = 10% / 100 = 0.10
  2. Place the values into the formula: P(2) = 30,000 (1 + 0.10)^2
  3. Calculate the growth for each year: P(2) = 30,000 (1.10)^2
  4. Solve the exponent: P(2) = 30,000 x 1.21
  5. Find the future population: P(2) = 36,300

Therefore, the population of the village after 2 years will be 36,300.

User Kapa
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