Final answer:
The molar mass of magnesium hydroxide, Mg(OH)2, is calculated by adding the molar masses of magnesium, oxygen, and hydrogen, resulting in a total molar mass of 58 g/mol.
Step-by-step explanation:
To calculate the molar mass of magnesium hydroxide, Mg(OH)2, we need to add the molar masses of magnesium, oxygen, and hydrogen according to the formula. Magnesium hydroxide contains one magnesium atom, two oxygen atoms, and two hydrogen atoms.
The molar mass of magnesium (Mg) is 24 g/mol. Each oxygen atom (O) has a molar mass of 16 g/mol, so two oxygen atoms will contribute 2 × 16 g/mol = 32 g/mol. Hydrogen (H) has a molar mass of 1 g/mol, so two hydrogen atoms will contribute 2 × 1 g/mol = 2 g/mol.
Adding these together:
- Molar mass of Mg = 24 g/mol
- Molar mass of O = 32 g/mol (2 × 16 g/mol)
- Molar mass of H = 2 g/mol (2 × 1 g/mol)
Total molar mass of Mg(OH)2 = 24 g/mol + 32 g/mol + 2 g/mol = 58 g/mol.