Question

Astronauts brought a feather and a hammer into space because they felt like it. They are dropped on the moon from a height of 1.72 meters. The acceleration due to gravity near the surface of the moon is 1.63m/s2. Find the time in seconds?

Answer 1

Using the kinematic equation for uniformly accelerated motion, it takes approximately 1.46 seconds for a feather and a hammer to fall to the moon's surface from a height of 1.72 meters with an acceleration due to gravity of 1.63m/s².

Step-by-step explanation:

To find the time it takes for a feather and a hammer to fall to the surface of the moon from a height of 1.72 meters with an acceleration due to gravity of 1.63m/s2, we use the kinematic equation for uniformly accelerated motion without initial velocity:

s = ½ at2

Here, s is the distance (1.72 meters), a is the acceleration due to gravity (1.63 m/s2), and t is the time in seconds which we need to find. Solving for t:

1.72 = ½ × 1.63 × t2
t2 = ×2 × 1.72 / 1.63
t2 = 2.12
t = √2.12
t ≈ 1.46 seconds

Therefore, it takes approximately 1.46 seconds for the feather and hammer to fall to the moon's surface from a height of 1.72 meters.