163k views
0 votes
what is the half life of a radioactice isotope if it takes 6.2 days for a 72 gm sample to decay to 18 gm

1 Answer

2 votes

Final answer:

The half-life of the radioactive isotope is approximately 2.483 days.

Step-by-step explanation:

The half-life of a radioactive isotope can be determined using the formula:

T1/2 = (ln 2) / k

Where T1/2 is the half-life, and k is the decay constant.

In this case, we are given that a 72 gm sample decays to 18 gm in 6.2 days. To find the half-life, we need to solve for k:

k = (ln(initial mass/final mass)) / time

k = (ln(72 gm/18 gm)) / 6.2 days

k = (ln(4)) / 6.2 days

Using the value of k, we can calculate the half-life:

T1/2 = (ln 2) / k

T1/2 = (ln 2) / ((ln(4)) / 6.2 days)

T1/2 ≈ 2.483 days

User Altherius
by
7.0k points