Question

During the collision, the impulse on the block of mass 6M has magnitude J. The impulse on the block of mass 4M during the collision has magnitude?

a. 2J/3
b. 3J/4
c. 4J/3
d. 3J/2

Answer 1

The impulse on the block of mass 4M during the collision is 14J.

Step-by-step explanation:

The impulse on the block of mass 4M during the collision can be calculated using the principle of conservation of momentum. Since momentum is conserved in a collision, the total momentum before the collision is equal to the total momentum after the collision.

Let the initial velocity of the block with mass 6M be v1 and the initial velocity of the block with mass 4M be v2. The total momentum before the collision is given by:

Total initial momentum = 6Mv1 + 4Mv2

The total momentum after the collision is also given by:

Total final momentum = (6M + 4M)(v1+v2)

Since the impulse on the block with mass 6M has magnitude J, we can calculate the impulse on the block with mass 4M as:

Impulse on block with mass 4M = (6M + 4M)(v1+v2) - 6Mv1

Impulse on block with mass 4M = 10Mv2 + 4Mv1

Therefore, the impulse on the block with mass 4M during the collision has magnitude 10J + 4J = 14J.