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33 votes
33 votes
Find the equation of the straight line passing through each of the following pairs of points.

(16 , 13) and (4, -5)

User Paddyfields
by
3.0k points

1 Answer

14 votes
14 votes

Answer:

y =
(3)/(2) x - 11

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = (16, 13 ) and (x₂, y₂ ) = (4, - 5 )

m =
(-5-13)/(4-16) =
(-18)/(-12) =
(3)/(2) , then

y =
(3)/(2) x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (12, 13 ) , then

13 = 24 + c ⇒ c = 13 - 24 = - 11

y =
(3)/(2) x - 11 ← equation of line

User Jeenyus
by
3.1k points