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A 53.0 kg sled is on snow with μₛ 0.0888. What is the maximum static friction force on the sled?

User HyperCube
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Final answer:

The maximum static friction force on the sled is 42.90 N.

Step-by-step explanation:

The maximum static friction force on the sled can be determined using the formula fs(max) = μsN, where μs is the coefficient of static friction and N is the normal force. In this case, the normal force is equal to the weight of the sled, which can be calculated as N = mg, where m is the mass of the sled and g is the acceleration due to gravity. Substituting the given values, we have fs(max) = μs(mg).

Therefore, fs(max) = (0.0888)(53.0 kg)(9.8 m/s^2) = 42.90 N. So, the maximum static friction force on the sled is 42.90 N.

User Jax Teller
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