Question

A jug has a maximum capacity of 4 liters. It's filled to 85% of its capacity, and then poured

out at a rate of 25 mL/s. Which of the following expressions models the volume remaining in
the jug, in liters, after x seconds?
A 3.4 -0.025x
B 4 -0.025x
C 3400 - 25x
D 4000 – 25x

Answer 1

The correct expression modeling the volume remaining in the jug after x seconds is 3.4 - 0.025x. This accounts for the initial volume of 3.4 liters and the pour out rate of 25 mL/s, converted to 0.025 L/s.

Step-by-step explanation:

To find the volume remaining in the jug after x seconds, we need to account for the volume poured out over time. First, since the jug has a maximum capacity of 4 liters and is initially filled to 85% of its capacity, we calculate the initial volume in the jug:

4 liters × 0.85 = 3.4 liters.

Next, the jug is being poured out at a rate of 25 mL/s. To express this rate in liters per second, we convert milliliters to liters knowing that 1,000 mL = 1 L:

25 mL/s = 25 / 1,000 L/s = 0.025 L/s.

This flow rate needs to be multiplied by the time in seconds that has passed, which is x. We subtract this volume from the initial volume to get the volume remaining after x seconds:

3.4 liters - (0.025 L/s × x seconds).

The expression that models the volume remaining in the jug after x seconds is:

3.4 - 0.025x