Question

A car is moving at

3.06m/s north.
There are 5 forces acting on it. A 6.59N force of air resistance to the south. A 8,507.74N force of gravity pulling it toward the ground. A 8,507.74N normal force pushing it up away from the ground. A 147.43N force from the engine pushing it
North, and a 22.81N force of friction
pulling it south.
Calculate the net force on the car.

Answer 1

Step-by-step explanation:

Given:

V = 3.06 m/s (North)

F₁ = 6.59 N (South)

F₂ = 8 507.74 N (toward the ground)

F₃ = 8 507.74 N ( up away from the ground)

F₄ = 147.43 (North)

F₅ = 22.82 (South)

__________

R -?

Forces F₂ and F₃ balance each other.

Resultant force:

R = F₄ - F₁ - F₅

R = 147.73 - 6.59 - 22.81 = 118.33 N