Question

"An office manager is selecting a water delivery service. Acme H₂O charges a $15 fee and $7.50 per 5-gallon jug.

Best Water charges a $24 fee and $6.00 per 5-gállon jug. How many 5-gallon jugs will it take for Best Water to
be less than Acme H₂0?"

Answer 1

It will take 6 5-gallon jugs for Best Water to be less than Acme H₂O.

Step-by-step explanation:

To determine the number of 5-gallon jugs it will take for Best Water to be less than Acme H₂O, we can set up an equation to compare the total cost of each service.

Let x represent the number of 5-gallon jugs.

Acme H₂O's total cost: 15 + 7.5x

Best Water's total cost: 24 + 6x

We want to find the value of x when Best Water's total cost is less than Acme H₂O's total cost.

24 + 6x < 15 + 7.5x

Combining like terms:

-1.5x < -9

Dividing both sides by -1.5, flipping the inequality sign since we're dividing by a negative number:

x > 6

Therefore, it will take 6 5-gallon jugs for Best Water to be less than Acme H₂O.