Question

If 15 g of C₂H₄reacted in the reaction below, then how many grams of O₂ must have also reacted? (Make sure to use the balanced version of this equation.)

Answer 1

If 15g of C2H4 reacted, then approximately 25.7g of O2 must have also reacted.

Step-by-step explanation:

The balanced chemical equation for the reaction is:

2 C2H4 + 3 O2 → 4 CO2 + 4 H2O

From this equation, we can see that for every 2 moles of C2H4, we need 3 moles of O2. Since we are given 15g of C2H4, we can convert this to moles using the molar mass:

15g C2H4 * (1 mole C2H4 / 28g C2H4) = 0.536 moles C2H4

Using the mole ratio, we can calculate the amount of O2 required:

0.536 moles C2H4 * (3 moles O2 / 2 moles C2H4) = 0.804 moles O2

To find the mass of O2, we can multiply the moles by the molar mass of O2:

0.804 moles O2 * (32g O2 / 1 mole O2) ≈ 25.7g O2