Question

A story about the distribution of a treasure tells that a colonel and three soldiers identified as A, B and C found a chest with more than 230 gold bars and less than 250. He decided that the next day he would distribute them among the soldiers to reward their courage, however, soldier A came forward and counted the bars, took a third part and got rid of one that was left over so that the distribution was equal. Shortly after, soldier B did the same counted, took a third part and was undone of one that was left over, then soldier C counted the bars, he took a third and got rid of one that was left over. The next morning the colonel prepared to distribute the treasure, he thought it was all the gold, so he divided it into three equal parts and as there was one left, he decided to keep it. How many bars did each soldier receive?

Answer 1

Soldier A, Soldier B, and Soldier C each received 229 gold bars.

Step-by-step explanation:

The story states that soldier A took a third of the gold bars and got rid of one that was left over, soldier B did the same, and soldier C did the same. This means that each soldier took a third and got rid of one, leaving them with 2/3 of the original amount.

Since the colonel divided the remaining gold into three equal parts and kept the remaining bar for himself, we can conclude that the remaining gold was one bar. Therefore, each soldier received 2/3 of the original amount plus one bar.

To find the number of gold bars each soldier received, we need to solve the inequality: 2/3x + 1 = 230, where x represents the number of gold bars each soldier received.

Solving this inequality, we find that each soldier received 229 gold bars.