Question

What values are excluded from the domain of the function?
F(x)=1/x-1
H(x)=x+3/x+8

Answer 1

The values excluded from the domain of the function f(x) = 1/(x-1) are x = 1. There are no values excluded from the domain of the function h(x) = (x+3)/(x+8).

Step-by-step explanation:

The values excluded from the domain of the function f(x) = 1/(x-1) are those that make the denominator equal to zero. So, x-1 = 0, which means x = 1. Therefore, the value 1 is excluded from the domain of the function f(x) = 1/(x-1).

For the function h(x) = (x+3)/(x+8), there are no values excluded from the domain. This is because there are no values of x that would make the denominator (x+8) equal to zero. So, all real numbers are included in the domain of the function h(x) = (x+3)/(x+8).