Question

Find tan 0 if sin=3/4 and 0 is in quadrant 2

Answer 1

`-(3)/(√(7) ) .`

Explanation:

1) tanΘ=sinΘ/cosΘ;

`2) \ cos \theta=^+_-√(1-sin^2 \theta); \ = > \ cos \theta=^+_-(√(7))/(4);`

3) if according to the initial condition Θ is in II-quadrant, then the cosΘ<0!

`cos \theta=-(√(7))/(4) ;`

4) finally,

`tan \theta=(sin \theta)/(cos \theta)=-(3)/(√(7)).`