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boat travels 22.0 m while it reduces its velocity from 12.5 m/s to 3.5 m/s. What is the magnitude of the boat’s acceleration while it travels the 12.0 m?

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Final answer:

The boat's acceleration while it travels 22.0 m is approximately 0.39 m/s^2.

Step-by-step explanation:

The magnitude of the boat's acceleration can be calculated using the equation:

acceleration = (final velocity - initial velocity) / time

Given that the boat travels 22.0 m, and the velocity reduces from 12.5 m/s to 3.5 m/s, we can calculate the time using the equation:

displacement = (initial velocity + final velocity) / 2 * time

Using these equations:

acceleration = (3.5 m/s - 12.5 m/s) / time

22.0 m = (3.5 m/s + 12.5 m/s) / 2 * time

Substituting the second equation into the first, we can solve for the time:

acceleration = (3.5 m/s - 12.5 m/s) / ((3.5 m/s + 12.5 m/s) / 2 * time)

Simplifying, we find that the magnitude of the boat's acceleration is approximately 0.39 m/s2.

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