Final answer:
The offspring from a cross between a homozygous recessive (ss) mother and a heterozygous (Ss) father will have genotypes 50% Ss and 50% ss, and their phenotypes will be 50% with a smooth coat and 50% with a rough coat.
Step-by-step explanation:
The question involves a genetic cross between two individuals, with the mother being homozygous recessive (ss) and the father being heterozygous (Ss) for a particular trait. To determine the genotypes and phenotypes of the offspring, we use a Punnett square.
Since the mother can only contribute an 's' allele and the father can contribute either an 'S' or an 's', the possible genotypes of the offspring are: 50% Ss (heterozygous) and 50% ss (homozygous recessive). As 'S' (smooth coat) is dominant to 's' (rough coat), the phenotypic ratio will be 50% smooth coat and 50% rough coat, assuming 'S' codes for smooth coat and 's' codes for rough coat based on the context provided.
The genotypes of the offspring will be 50% Ss and 50% ss. The phenotypes will be 50% smooth coat and 50% rough coat.