Final answer:
The offspring of an EE father and an ee mother would all have the genotype Ee, which is heterozygous. As a result, they would all express the dominant phenotype corresponding to the E allele because the E allele masks the recessive e allele.
Step-by-step explanation:
The question pertains to the phenotypic ratio of offspring resulting from a cross between an EE father (homozygous dominant) and an ee mother (homozygous recessive). Since the father carries two dominant alleles (E) and the mother carries two recessive alleles (e), all their offspring will inherit one dominant allele from the father and one recessive allele from the mother, resulting in a genotype of Ee for each offspring. Considering that the dominant allele E would mask the expression of the recessive allele e, all offspring would exhibit the dominant phenotype.
Illustrating this with Mendelian genetics, the cross would be EE (father) x ee (mother). The offspring would therefore inherit an E from the father and an e from the mother. This means that each offspring would have the genotype Ee, which is heterozygous. Because the dominant trait is represented by E, the phenotype of all offspring would be determined by the dominant trait represented by the allele E. In the context of Mendel's pea plant experiments, if the trait E represented yellow seed color and the trait e represented green seed color, all the offspring would have yellow seeds, following the principle of complete dominance where the dominant allele completely masks the recessive one in a heterozygote.