Question

A 1,500-kg car is moving to the right at 14 m/s before it crashes into a wall and bounces back to the left at 6 m/s. The impact lasts for 0.5 seconds, what is the average force exerted during the impact

Answer 1

The average force exerted during the impact is -60000 N.

Step-by-step explanation:

To calculate the average force exerted during the impact, we can use the formula:

force = (change in momentum) / (time interval)

First, let's calculate the change in momentum:

magnitude of change in momentum = (mass of car) * (final velocity - initial velocity)

Let's plug in the values:

magnitude of change in momentum = (1500 kg) * ((-6 m/s) - 14 m/s)

Next, we need to determine the direction of the change in momentum. Since the car is initially moving to the right and bounces back to the left, the change in momentum is negative.

Therefore, the change in momentum is -30000 kg*m/s.

Now, let's calculate the average force:

average force = (-30000 kg*m/s) / (0.5 s)

average force = -60000 N

So, the average force exerted during the impact is -60000 N.