Final answer:
The larger number is four times greater than the smaller number once we perform the operation described in the problem.
Step-by-step explanation:
Let us denote the smaller number as s and the larger one as l. The problem states that if we subtract a quarter of the smaller number (s/4) from both numbers, the new value of the larger number becomes five times the new value of the smaller number.
So, the equations representing the situation are:
- l - (s/4) = 5*(s - (s/4))
- l - s/4 = 5s - 5s/4
- l - (s/4) = 4s/4
We simplify to find the ratio l/s.
Thus, the larger number l is four times greater than the smaller number s.