Question

Jarrett and Andrew decided to take a trip up north to the U.P.. On the way up, they get pulled over for doing 150 km/s, as Jarrett pulled over it took him 10 s to slow down to a complete stop. What is his acceleration?

Answer 1

Jarrett's car decelerates from an initial velocity of 150,000 m/s to 0 m/s in 10 seconds, resulting in an acceleration of -15,000 m/s².

Step-by-step explanation:

The student's question involves calculating the acceleration of a car as it slows down to a complete stop. To find the acceleration, we use the formula a = Δv / Δt, where Δv is the change in velocity and Δt is the change in time. Given that Jarrett's car goes from 150 km/s to 0 km/s in 10 seconds, we first need to convert the speed from km/s to m/s by multiplying by 1,000. So, Jarrett's initial velocity is 150,000 m/s. The final velocity is 0 m/s, and the time taken to stop is 10 s. Thus, the acceleration is calculated as:

a = (0 m/s - 150,000 m/s) / 10 s = -150,000 m/s² / 10 s = -15,000 m/s²

This value is negative because the car is decelerating (slowing down).