Final answer:
To determine the grams of product formed in the synthesis reaction, we calculate the moles of SO3 formed using the mole ratio between oxygen and SO3. Then, we multiply the moles of SO3 by its molar mass to find the grams of SO3 formed. In this case, 4.8 moles of O2 would react to form 768.6 grams of SO3.
Step-by-step explanation:
To determine the grams of product formed in the synthesis reaction 2SO2(g) + O2(g) → 2SO3(g), we need to calculate the mole ratio between oxygen and SO3. From the balanced equation, we know that 1 mole of O2 reacts with 2 moles of SO3. Therefore, if 4.8 moles of O2 reacted, we can calculate the moles of SO3 formed using the mole ratio.
4.8 moles O2 * (2 moles SO3 / 1 mole O2) = 9.6 moles SO3
Next, we can calculate the mass of SO3 formed by multiplying the moles of SO3 by its molar mass. The molar mass of SO3 is 80.06 g/mol.
9.6 moles SO3 * 80.06 g/mol = 768.6 grams
Therefore, 768.6 grams of SO3 would be formed when 4.8 moles of O2 react.