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Your cousin was standing along a parade was traveling route when she spotted a float 750 ft from her. the parade was traveling at 158ft/min. the distance d from your cousin in feet after t minutes is given by d = |750-158ft|. At what times is the float 200ft from your cousin? Round to the nearest tenth.

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Final answer:

To find the times when the float is 200 ft from your cousin, solve the equation |750 - 158t| = 200, resulting in two possible times, approximately 3.5 minutes and 6.0 minutes.

Step-by-step explanation:

To determine when the parade float is 200 ft from your cousin, we start with the equation given for the distance, d from your cousin in feet after t minutes, which is d = |750 - 158t|. To find out the times when the float is 200 ft away, we set the equation equal to 200 and solve for t.

We have two cases to consider due to the absolute value:

750 - 158t = 200

750 - 158t = -200

Solving each equation for t will give us the times when the float is 200 ft away:

158t = 550

158t = 950

Dividing 550 by 158 and rounding to the nearest tenth, we get approximately t = 3.5 minutes. Dividing 950 by 158 and rounding to the nearest tenth, we get approximately t = 6.0 minutes. These are the two times when the float is 200 ft away from your cousin.

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