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How much sodium chloride is required to produce 5 L of 0.85?

User Moander
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Final answer:

To prepare 500 cm³ (0.5 L) of a 0.01 M NaCl solution, you need 0.2922 grams of sodium chloride, using the molar mass of NaCl which is 58.44 g/mol.

Step-by-step explanation:

Calculating Mass of Sodium Chloride for a Solution

To calculate how much sodium chloride (NaCl) is needed to prepare a 0.01 M solution in 500 cm³ (or 0.5 L), we can use the formula:

mass = molarity × volume × molar mass

First, convert the volume from cm³ to L by dividing by 1000:

500 cm³ = 0.5 L

The molar mass of NaCl is approximately 58.44 g/mol. Now, plug the values into the formula:

mass = 0.01 mol/L × 0.5 L × 58.44 g/mol

mass = 0.2922 g of NaCl

So, you would need 0.2922 grams of NaCl to prepare 500 cm³ of a 0.01 M NaCl solution.

User Luca Di Liello
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