Final answer:
To determine the equilibrium concentration of H₂ in the reaction H₂ + I₂ <=> 2 HI, the equilibrium constant expression is used. After substituting the given values for [HI] and [I₂] and the equilibrium constant (Keq), [H₂] is calculated to be 0.010 M. This calculated value does not match any of the provided options, suggesting a possible error in the given values or question.
Step-by-step explanation:
To find the equilibrium concentration of H₂, we use the given chemical equilibrium expression:
H₂ + I₂ <=> 2 HI
For the reaction, the equilibrium constant expression (Keq) is given by:
Keq = [HI]2 / ([H₂] [I₂])
We know that:
- Keq = 0.40
- [HI] = 0.060 M
- [I₂] = 0.90 M
Substituting these values into the equilibrium expression, we get:
0.40 = (0.060)2 / ([H₂] * 0.90)
Now, let's perform the calculations to find [H₂]:
0.40 = 0.0036 / (0.90[H₂])
[H₂] = 0.0036 / (0.40 * 0.90)
[H₂] = 0.0036 / 0.36
[H₂] = 0.010 M
However, the options provided do not include this value, indicating that there might be a miscommunication with the options. Let's compare our calculated value of 0.010 M with the options given:
- 0.4
- 0.5
- 0.6
- 0.7
None of these match our calculated value, suggesting the need to clarify the provided options or the initial problem statement.