In a cross between a homozygous dominant (BB) male rabbit and a heterozygous (Bb) female, all offspring are expected to have black fur (100%), as black is dominant over white.
Let's use Punnett square rules to complete this question.
The genotype of the male rabbit (BB) is homozygous dominant, and the genotype of the female rabbit (Bb) is heterozygous. We can set up a Punnett square to explore the possible genotypes of their offspring:
| B | B |
---|---|---|
B | BB| BB|
b | Bb| Bb|
Now, let's determine the phenotypes. Since black fur (B) is dominant, any individual with at least one B will express black fur. The phenotypic ratio can be determined from the genotypic ratio:
- Black fur (BB or Bb): 4 (BB) + 4 (Bb) = 8
- White fur (bb): 0
So, the percent chance for the phenotypes of the offspring is:
- Black fur: (8 / 8) * 100% = 100%
- White fur: (0 / 8) * 100% = 0%
All offspring are expected to have black fur based on the given genetic cross.