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22 OXYZ is a parallelogram. OX = a OY = b R P P is the point on OX such that OP: PX=1:2 R is the point on OY such that OR: RY= 1:3 Work out, in its simplest form, the ratio ZP: ZR You must show all your working. X Y​

22 OXYZ is a parallelogram. OX = a OY = b R P P is the point on OX such that OP: PX-example-1
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In the parallelogram OXYZ, with OX = a and OY = b, points P and R on OX and OY respectively are established. The simplified ratio ZP:ZR is (5a - 12b) : (8a + 3b).

In the parallelogram OXYZ, let's denote the point P on OX such that OP:PX = 1:2, and the point R on OY such that OR:RY = 1:3.

1. Express OP and PX in terms of a:


OP = (1)/(3) \cdot a (since \(OP:PX = 1:2\))


PX = (2)/(3) \cdot a

2. Express OR and RY in terms of b:


OR = (1)/(4) \cdot b (since \(OR:RY = 1:3\))


RY = (3)/(4) \cdot b

Now, we want to find the ratio ZP:ZR, where Z is the intersection of PR and QY.

ZP = OP - OZ

ZR = RY - OZ

3. Express OZ in terms of a and b:


OZ = OY - YZ = b - (2)/(3) \cdot a (since \(OY = b\) and \(YZ = (2)/(3) \cdot a\))

Now, substitute these values into ZP and ZR:


ZP = (1)/(3) \cdot a - (b - (2)/(3) \cdot a)


\[ ZR = (3)/(4) \cdot b - (b - (2)/(3) \cdot a) \]

4. Simplify the expressions:


ZP = (5)/(3) \cdot a - b


ZR = (2)/(3) \cdot a + (1)/(4) \cdot b

5. Find the ratio ZP:ZR:


ZP:ZR = ((5)/(3) \cdot a - b) : ((2)/(3) \cdot a + (1)/(4) \cdot b)

So, the simplified ratio ZP:ZR is (5a - 12b) : (8a + 3b).

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