Question

A certain animal is known to have a series of multiple alleles for coat color such that aR (red) is dominant to aP (pink) which in turn is dominant to aS (sable) which is dominant to a (albino). An aRaP individual is crossed with a sable of genotype aSa. What ratio of progeny would be expected?

Answer 1

A cross between a multiple allelic individual with genotype aRaP and a sable individual with genotype aSa would result in a 1:1:1:1 phenotypic ratio of red, pink, sable, and albino-coated offspring.

Step-by-step explanation:

The question is about inheritance and the concept of multiple alleles and dominance. In this scenario, given that aR (red) is dominant to aP (pink), which is dominant to aS (sable), which is dominant to a (albino), we can predict the outcomes of the cross between an individual of genotype aRaP and one that is sable with genotype aSa.

To solve this, we need to create a Punnett square with one parent contributing either the aR or aP allele, and the other parent contributing either the aS or a allele. The possible genotypes for the offspring are:

• aRaS (red coat color)
• aPaS (pink coat color)
• aRa (sable coat color)
• aPa (albino coat color, because aP is not dominant to a)

The expected phenotypic ratio of the progeny will be 1 red: 1 pink: 1 sable: 1 albino.