Final answer:
The genotype e+ / e+ is a homozygous (option 1) genotype with two identical wild-type alleles, indicating it's the most common or 'normal' allele, typically dominant in nature.
Step-by-step explanation:
The genotype e+ / e+ is a homozygous genotype because it contains two identical wild-type alleles. Being homozygous means having two of the same allele, whether they are dominant or recessive.
The term 'wild-type' typically refers to the most common phenotype or genotype observed in the natural population, often denoted with a '+' sign. This genotype indicates two dominant alleles because the wild type is generally considered the dominant allele.
In contrast, a heterozygous genotype would have one dominant and one recessive allele, denoted as Aa or aA. When there are two different alleles present, it's heterozygous. The genotype e+ / e+ does not fit this description as both alleles are the same. Thus, the correct option for this genotype is '1) Homozygous'.