166k views
1 vote
Solve the equation a^3-4a^2+4a

User Burtek
by
8.5k points

1 Answer

3 votes

Final answer:

The expression a^3 - 4a^2 + 4a factors as a(a - 2)^2. Setting it equal to zero and applying the zero-product property provides the solutions as a = 0 and a = 2, with a = 2 being a repeated root.

Step-by-step explanation:

To solve the equation a^3 - 4a^2 + 4a, we need to first note that it's not a quadratic equation as initially indicated; instead, it is a cubic equation. However, this cubic equation can be factored by recognizing it as a times a perfect square trinomial. The expression can be factored as a(a^2 - 4a + 4). The quadratic part of the expression, a^2 - 4a + 4, further factors into (a - 2)^2; this reveals that the original expression is equivalent to a(a - 2)^2.

To find the solutions to the equation, we set it equal to zero: a(a - 2)^2 = 0. By applying the zero-product property, we can determine that a = 0 or (a - 2) = 0. Solving these will give us the roots of the equation, which are a = 0 and a = 2, with a = 2 being a repeated root due to the square.

User Mwhs
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.