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A cheerleader lifts his 68.6 kg partner straight up off the ground a distance of 0.601 m before releasing her. Assume the partner’s velocity is zero at the beginning and the end of the lift. The acceleration
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11 votes
11 votes
A cheerleader lifts his 68.6 kg partner straight

up off the ground a distance of 0.601 m before
releasing her. Assume the partner’s velocity
is zero at the beginning and the end of the lift.
The acceleration of gravity is 9.8 m/s
2
.
If he does this 30 times, how much work has
he done?
Answer in units of J.

User ShinyJos
by
2.6k points

2 Answers

13 votes
13 votes

Answer: 12121.2084

Step-by-step explanation:

User Thalecress
by
2.9k points
11 votes
11 votes

Answer:

12 121 J

Step-by-step explanation:

PE gained each time = m g h

now 30 times: 30 mgh = 30 * 68.6 * 9.8 * .601 = 12 121 J

User Ron Piggott
by
2.3k points
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