$7000 invested at 4% compounded continuously for 9 years yields approximately $10,026.55.
The formula for compound interest compounded continuously is given by:
![\[ A = P \cdot e^(rt) \]](https://img.qammunity.org/2024/formulas/mathematics/college/ysr6l6uh9s05s689f89gtobzf0p40d9t26.png)
where:
- A is the amount after time t,
- P is the principal amount (initial investment),
- r is the annual interest rate (in decimal form),
- t is the time in years,
- e is the mathematical constant approximately equal to 2.71828.
In your case:
- P = 7000,
- r = 0.04 (4% expressed as a decimal),
- t = 9 years.
![\[ A = 7000 \cdot e^(0.04 \cdot 9) \]](https://img.qammunity.org/2024/formulas/mathematics/college/y41qkqccvof858z1hx9o6se4ijw00bkb58.png)
Let's calculate this:
![\[ A = 7000 \cdot e^(0.36) \]](https://img.qammunity.org/2024/formulas/mathematics/college/nau36qgvvw3kchmtgidhb27j32kzzhfgs5.png)
Using a calculator:
![A \approx 7000 \cdot 1.432364654 \\\[ A \approx 10026.55 \]](https://img.qammunity.org/2024/formulas/mathematics/college/l7pa1cjtpd6g8rqi7r5sr4u8skjl0j86qc.png)
So, after 9 years, the amount, rounded to the nearest cent, would be approximately $10,026.55.