Question

An egg is dropped from a treehouse and takes 1.51.51, point, 5 seconds to reach the ground. We can ignore air resistance.

What is the egg's displacement?

Answer 1

The displacement of the egg is -7.35 meters.

Step-by-step explanation:

The displacement of the egg can be calculated using the equation:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Since the egg is dropped from rest, the initial velocity is 0 m/s. The acceleration due to gravity is -9.8 m/s^2 in the downward direction. Plugging in the values, the equation becomes:

displacement = 0 * 1.51.51, point, 5 + (1/2) * (-9.8) * (1.51.51, point, 5)^2

Simplifying the equation gives:

displacement = 0 + (-7.35) = -7.35 m

The negative sign indicates that the egg falls downwards, so the displacement is -7.35 meters.

Answer 2

The egg's displacement is 122.625 m

Here, the case of dropping the egg from the treehouse is comes under freefall condition. Meaning that the motion is under Earth's gravitational acceleration only as we have to ignore air resistance. Here initial velocity is considered to be zero.

Hence, we will use s= 1/2* g*t²

s is displacement to be find out in meter

g is acceleration due to gravity = 9.81 m/s²

t is time taken by the egg to reach the ground which is given as 5 second.

Putting all the values in the given equation

s= 1/2*9.81*5*5

s= 1/2*9.81*25

s= 245.25/2

s= 122.625

So the displacement is 122.625 meter