Question

You push a box across the floor at a constant speed of 1 m/s, applying a horizontal constant force of magnitude 20 N. Your friend pushes the same box across the same floor at a constant speed of 2 m/s, applying a horizontal force. What is the magnitude of the force that your friend applies to the box

Answer 1

the force your friend applied on the box is 40 N.

Step-by-step explanation:

Given;

speed of the box, v₁ = 1 m/s

force applied to the box, F₁ = 20 N

the speed of the box when your friend pushes it, v₂ = 2 m/s

then your friends applied force, F₂ = ?

Assuming the time, t, through which both forces were applied and mass of the box, m, to be constant;

`F_1 = (mv_1)/(t) \\\\(m)/(t) = (F_1)/(v_1) = (F_2)/(v_2)`

`F_2 = (F_1v_2)/(v_1) \\\\F_2 = (20* 2)/(1) \\\\F_2 = 40 \ N`

Therefore, the force your friend applied on the box is 40 N.