Question

A coconut tree can reach a height of 25 m. If air drag is negligibly small, how fast is the coconut falling when it reaches the ground if it dropped from the top of the 25 m tree? A. 7.07 m/s B. 22.13 m/s C. 14.14 m/s D. 27.6 m/s

Answer 1

The coconut falling from a 25 m tall tree would reach a speed of approximately 22.13 m/s when it hits the ground, given that air resistance is negligible and using the equation v = √(2gh) with g as 9.81 m/s².

Step-by-step explanation:

The question is about the speed of a coconut when it hits the ground after falling from the top of a 25 m tall tree, assuming air resistance is negligible.

To solve this, we use the equation of motion under gravity, which states that the final velocity v of an object falling from rest under gravity is given by v = √(2gh), where g is the acceleration due to gravity (approximately 9.81 m/s²) and h is the height from which the object falls.

For a 25 m tall coconut tree, plugging in the values we get v = √(2 * 9.81 m/s² * 25 m).

This simplifies to v = √(490.25 m²/s²), which is approximately 22.13 m/s.

So, the coconut would be traveling at a speed of 22.13 m/s when it hits the ground, ignoring air drag.