Known :
m = 100 gr = 0.1 kg
T1 = 90°C
T2 = 110°C
Solution :
Since the system is isolated, we can assume that no heat transfer is allowed, hence the process is adiabatic
W = m • Cv • ∆T
W = (0.1)(4.2 kJ/kg·K)(110°C - 90°C)
W = 8.4 kJ/kg
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