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A coffee maker has a cone-shaped container to hold the coffee grounds. The radius of the container is 3
inches and the height is 7 inches. What is the volume, in cubic inches, of coffee grounds the container can
hold? Round your answer to the nearest hundredth and use 3.14 for T. (1 point)
cubic inches
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User Egris
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7.5k points

2 Answers

6 votes

Answer:

Explanation:

The volume of a cone is given by the formula V = (1/3)πr^2h, where r is the radius and h is the height of the cone. Substituting the given values, V = (1/3)(3.14)(3^2)(7) = (1/3)(3.14)(9)(7) = (1/3)(3.14)(63) = (3.14)(21) = 65.94 cubic inches. Rounding to the nearest hundredth, the volume of coffee grounds the container can hold is 65.94 cubic inches.Answer :boxed{65.94}.welcome

User MrkK
by
7.4k points
3 votes

Answer:

To calculate the volume of the cone-shaped container, we can use the formula for the volume of a cone, which is given by V = (1/3)πr^2h, where V is the volume, π is approximately 3.14, r is the radius, and h is the height.

Given: Radius (r) = 3 inches Height (h) = 7 inches

Using the formula: V = (1/3) 3.14 (3 inches)^2 7 inches V = (1/3) 3.14 9 square inches 7 inches V = (1/3) 3.14 63 cubic inches V ≈ 65.97 cubic inches

Therefore, the volume of coffee grounds the container can hold is approximately 65.97 cubic inches.

User Bobelev
by
7.7k points