Question

A 50.0 mL solution of Ca(OH)₂ with an unknown concentration was titrated with 0.340 M HNO₃. To reach the endpoint, a total of 19.3 mL of HNO₃ was required. What quantity in moles of HNO₃ are used in the titration

Answer 1

To find the moles of HNO3 used in the titration, multiply the volume of HNO3 used (converted to liters, 0.0193 L) by its molarity (0.340 M), resulting in 0.006561 moles of HNO3.

Step-by-step explanation:

To calculate the quantity in moles of HNO3 used in the titration, we use the volume of HNO3 added and its concentration. The volume of HNO3 in liters is 19.3 mL which is 0.0193 L. The concentration of HNO3 is 0.340 M. Using the formula:

Moles of HNO3 = Volume in liters × Concentration in Molarity

We can calculate the number of moles of HNO3 used in the titration:

Moles of HNO3 = 0.0193 L × 0.340 M = 0.006561 mol HNO3

Thus, 0.006561 moles of HNO3 were used to titrate the Ca(OH)2 solution.