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Assign airspeeds of not less than ____ knots to departing reciprocating engine and turboprop aircraft.

a) 50 knots
b) 60 knots
c) 70 knots
d) 80 knots

1 Answer

6 votes

Final answer:

To find the tire rotation rate in rev/min for a jet moving at 60.0 m/s with 0.85 m diameter tires, calculate the tire circumference and divide the jet's speed by this circumference, then convert the result from rev/s to rev/min.

Step-by-step explanation:

To solve for how many revolutions per minute (rev/min) the tires of a commercial jet are rotating at a speed of 60.0 m/s, we first need to find the circumference of the tires, which can be calculated as π times the diameter. The diameter given is 0.850 m, making the circumference:

Circumference = π × diameter = π × 0.850 m ≈ 2.67 m.

Since the speed of the jet is 60.0 m/s, you can determine how many meters are covered in one second and then how many revolutions by dividing by the circumference:

Revolutions per second = speed / circumference = 60.0 m/s / 2.67 m ≈ 22.47 rev/s.

To convert rev/s to rev/min, multiply by 60:

Revolutions per minute = 22.47 rev/s × 60 = 1348.2 rev/min

Therefore, the tires are rotating at approximately 1348 rev/min.

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