Question

Solve using the quadratic equationX^2 -4x -3 =0

Answer 1

`x = 2` ±
`√(7)`

Explanation:

Lets see the quadratic equation :

x = -b ±
`√(b^2 - 4ac)` / 2a

So now we have our quadratic :

`x^2 - 4x - 3 =0`

a = ?^2 (Exponent)

b = ?x (Variable)

c = ? (Constant)

So replace every variable in the quadratic equation with the ones in the quadratic formula.

x = -(-4) ± (-4)^2 - 4(1)(-3) / 2(1)

(Imagine (-4)^2 - 4(1)(-3) in a square root)

x = 4 ±
`√(16 - - 12)` / 2

x = 4 ±
`√(28)` / 2

Of course 28 isn't available for a square root property, so lets break it up :

x = 4 ±
`2√(7)` / 2

Simplify the radical :

`x = 2` ±
`√(7)`

^^^